4x+2[4-2(2x+2)]=2x-4

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Solution for 4x+2[4-2(2x+2)]=2x-4 equation:


Simplifying
4x + 2[4 + -2(2x + 2)] = 2x + -4

Reorder the terms:
4x + 2[4 + -2(2 + 2x)] = 2x + -4
4x + 2[4 + (2 * -2 + 2x * -2)] = 2x + -4
4x + 2[4 + (-4 + -4x)] = 2x + -4

Combine like terms: 4 + -4 = 0
4x + 2[0 + -4x] = 2x + -4
4x + 2[-4x] = 2x + -4

Remove brackets around [-4x]
4x + 2 * -4x = 2x + -4

Multiply 2 * -4
4x + -8x = 2x + -4

Combine like terms: 4x + -8x = -4x
-4x = 2x + -4

Reorder the terms:
-4x = -4 + 2x

Solving
-4x = -4 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-4x + -2x = -4 + 2x + -2x

Combine like terms: -4x + -2x = -6x
-6x = -4 + 2x + -2x

Combine like terms: 2x + -2x = 0
-6x = -4 + 0
-6x = -4

Divide each side by '-6'.
x = 0.6666666667

Simplifying
x = 0.6666666667

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